If the diameter of a carbon atom is 0.15 nm

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structureofatom

#1

If the diameter of a carbon atom is 0.15 nm, calculate the number of carbon atoms which can be placed side by side in a straight line across length of scale of length 20 cm long.


#2

Diameter of a carbon atom = 0.15 nm= 0.15 X ${{10}^{-9}}$ m
Length along which atoms are to . be placed = 20 cm= 0.2 m
Number of carbon atom which can be placed in the given length =
0.2 / 0 .15 x ${{10}^{-9}}$ = 0.2 x ${{10}^{9}}$ / 0.15 m
= 1.33 x ${{10}^{9}}$ atoms