Molar Mass of methanol = C${{H}_{3}}$OH = 32 g / mol.
Moles of methanol in 2.5 L of its 0.25 M solution = 2.5 x 0.25 = 0.625 mole
Mass of methanol = 32 x 0.625 = 20g
.’. Volume required = = 0 025 L
Molar Mass of methanol = C${{H}_{3}}$OH = 32 g / mol.
Moles of methanol in 2.5 L of its 0.25 M solution = 2.5 x 0.25 = 0.625 mole
Mass of methanol = 32 x 0.625 = 20g
.’. Volume required = = 0 025 L