(ii) Now, a resistance of 10 $\Omega $ is connected in parallel with the series combination. Therefore, the total resistance of the circuit is given by
Thus, 1 A current will flow through 10 $\Omega $ resistor and 1 A will flow through the lamp and conductor of 5 $\Omega $ resistance. Hence, there will be no change in current flowing through 5 $\Omega $ conductor. Also, there will be no change in potential difference across the lamp.