An object 5 cm in length

cbse
refractionoflight

#1

An object 5 cm in length is held 25 cm away from a converging lens of focal length 10 cm. Find the position and nature of the image formed.


#2

Given u = -25 cm, f = 10 cm , v= ?

Lens formula 1/f = 1/v - 1/u

1/10 = 1/v - 1/-25 = 5-2/50

v = 50/3 = 16.66 cm

v/u = Size of the image/Size of the object

16.66/25 = Size of the image/5

Size of the image = 3.332 cm
So image is diminished.

Because the image distance is positive. So the image real lies between $F _{1}$ and $C _{1}$ The image is inverted and diminished.