Write the smallest digit and the greatest digit in the blank space of each of the following numbers so that the number formed is divisible by 3 :

**(a)** … 6724

**(b)** 4765 … 2

We know that a number divisible by 3, if the sum of its digits is divisible by 3.

**(a) … 6724**

For … 6724, we have 6 + 7 + 2 + 4 =19, we add 2 to 19, the resulting number 21 will be divisible by 3.

∴ The required smallest digit is 2.

Again, if we add 8 to 19, the resulting number 27 will be divisible by 3. .’. The required largest digit is 8.

**(b) 4765 … 2**

For 4765 … 2, we have 4 + 7 + 6 + 5 + 2 = 24, it is divisible by 3.

Hence the required smallest digit is 0.

Again, if we add 9 to 24, the resulting number 33 will be divisible by 3.

∴ The required largest digit is 9.