The angles of a triangle are in AP and no. of degrees in the least angle

The angles of a triangle are in AP and no. of degrees in the least angle is to no. of degrees in the mean angle as 1:120 find the angle in radians

let the angles are a-d,a,a+d.

so a-d+a+a+d=180 degree
3a=180 degree
a=60 degree
given that a-d/a=1/120
(60-d)/60=1/120
120-2d=1
d=119/2

so angles in radians will have

60-119/2=1/2 degree,60degree,60+119/2 =239/2 degree
in radians anlgles will be
pi/360,pi/3,239pi/360