The angles of a triangle are in AP and no. of degrees in the least angle is to no. of degrees in the mean angle as 1:120 find the angle in radians

let the angles are a-d,a,a+d.

so a-d+a+a+d=180 degree

3a=180 degree

a=60 degree

given that a-d/a=1/120

(60-d)/60=1/120

120-2d=1

d=119/2

so angles in radians will have

60-119/2=1/2 degree,60degree,60+119/2 =239/2 degree

in radians anlgles will be

pi/360,pi/3,239pi/360