Shanti Sweets Stall was placing an order for making cardboard boxes for packing their sweets. Two sizes of boxes were required. The bigger of dimensions 25 cm x 20 cm x 5 cm and the smaller of dimensions 15 cm x12 cm x 5 cm. For all the overlaps, 5% of the total surface area is required extra. If the cost of the cardboard is ₹4 for 1000 cm2, then find the cost of cardboard required for supplying 250 boxes of each kind.
Dimensions of bigger box are
l = 25 cm, b = 20 cm and h = 5 cm
∴ Total surface area of the bigger box
= 2(lb + bh + hl) = 2(25 x 20 + 20 x 5 + 5 x 25)
Dimensions of smaller box are
l= 15 cm, b = 12 cm and h = 5 cm
∴ Total surface area of the smaller box
= 2(15 x 12 + 12 x 5 + 5 x 15)
Total surface area of both boxes = Total surface area of bigger box + Total surface area of smaller box
