Prove that their centres lie on the perpendicular bisector of the common chord

If two circles intersect at two points, then prove that their centres lie on the perpendicular bisector of the common chord

Let two circles with centres O and P intersecting each other at A and B.
To prove OP is the perpendicular bisector of common chord AB.
Construction Join OA, OB, BP and PA. Let OP intersects AB at M.
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Hence, OP is the perpendicular bisector of AB.