Line / is the bisector of ∠A and B is any point on l. BP and BQ are perpendiculars from B to the arms of ∠A. Show that
(i) ∆APB = ∆AQB
(ii) BP = BQ or B is equidistant from the arms of∠A
Given Line l is the bisector of ∠A,
i.e. ∠QAB = ∠PAB
Also, BP and BQ are perpendiculars to the arms of ∠A.
i.e. ∠BQA = ∠BPA = 90°
