In the given figures, two sides AB, BC and the median AD of ∆ABC are correspondingly equal to the sides PQ, QR and the median PM of ∆PQR.

Given AD is median of ∆ABC and PM is median of ∆PQR.

Also, AB = PQ, BC = QR and AD = PM

Proof In ∆ABD and ∆PQM, AB= PQ [given]

AD = PM [given]

and BD =QM

In ∆ABC and ∆PQR, we have

AB = PQ [given]

and ∠B =∠Q [proved above]

BC =QR [given]