In the given figures, two sides AB, BC and the median AD of ∆ABC are correspondingly equal to the sides PQ, QR and the median PM of ∆PQR.
Given AD is median of ∆ABC and PM is median of ∆PQR.
Also, AB = PQ, BC = QR and AD = PM
Proof In ∆ABD and ∆PQM, AB= PQ [given]
AD = PM [given]
and BD =QM
In ∆ABC and ∆PQR, we have
AB = PQ [given]
and ∠B =∠Q [proved above]
BC =QR [given]
