In the given figure, side BC of tSABC is produced to form ray BD and CE 11 BA. Show that ZACD = ZA + ZB. Deduce that
ZA + ZB + ZC = 180°.
In the given figure, side BC of tSABC is produced to form ray BD and CE 11 BA. Show that ZACD = ZA + ZB. Deduce that
ZA + ZB + ZC = 180°.