Construct a ∆ABC whose perimeter is 8.2 cm and the base angles are 45° and 60°.

(i) First, draw PQ = 8.2 cm.

(ii) At point P, construct ∠RPQ = 60° and at point Q,

construct ∠SQP = 45°.

(iii) Draw bisector of ∠RPQ and∠SQP, which intersect each other at point A.

(iv) Join AP and AQ.

(v) Draw perpendicular bisector of AP which intersects PQ at point B and also draw perpendicular bisector of AQ which intersects PQ at point C.

(vi) Join AB and AC Thus, we get the required ∆ABC.