Calcutate the volume occupied by 28u nitrogen gas?

Dhanalakshmi · July 16, 2019, 4:57am

calcutate the volume occupied by 28u nitrogen gas ?

Dhanalakshmi · July 16, 2019, 4:58am

Molecular mass of nitrogen = 28 u
28 u nitrogen gas = 1 molecule of N
1 mole of nitrogen gas at STP occupies = 22.4 L
That meas 6.023 × 10²³molecules of N occupies = 22.4 L
Hence, 28 u occupies = 22.4 / 6.023 × 10²³ = 3.71 × 10^-23 L