Since 22400 $c{{m}^{3}}$ of hydrogen at STP weight = 2g Therefore, 112 $c{{m}^{3}}$ of hydrogen at STP weight
= 2/22400 X 112 = 0 01 g
Since 22400 $c{{m}^{3}}$ of hydrogen at STP weight = 2g Therefore, 112 $c{{m}^{3}}$ of hydrogen at STP weight
= 2/22400 X 112 = 0 01 g