Atomic number of aluminium is 13 and mass number is 27. Calculate the number of electrons, protons and neutrons in its atom. Represent the ion of this element.
Number of electrons = 13
Number of protons =13
Number of neutrons = 27 —13 =14
Its electronic configuration is 2,8, 3(K,L,M)
As it may lose 3 electrons easily to achieve completely filled outermost shell and hence become stable, it acquires a positive charge of +3. Therefore, its ion is represented as $A{{l}^{3+}}$