Side of the cube = 10 cm

Its volume = 10 x 10 x 10 = 1000 cm^3 = 10^-3 m^3

Area of the face of the cube = 10 x 10 = 100 cm^2

= 10^-2 m^2

Density of iron = 8000 kg m^-3 Therefore, mass ‘m’ of the iron cube

= 8000 x 10^-3 kg = 8 kg

Pressure on the portion of the table in contact with the table

Pressure = Weight / Area

= 8 x 10 / 10^-2

= 8 x 10^3 Pa