ABCD is a cyclic quadrilateral. A circle passing through A and B meet AD

ABCD is a cyclic quadrilateral. A circle passing through A and B meet AD and BC in points E and F respectively prove that EF is parallel to DC.

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ABFE is a cyclic quadrilateral.
Opposite angles of a cyclic quadrilateral are supplementary.
x + y = 180°
Also,
x + z = 180°
x + y = x + z
y = z
As these are corresponding angles EF is parallel to DC.