A hemispherical bowl is made from a metal sheet having thickness 0.3 cm. The inner radius of the bowl is 24.7 cm. Find the cost of polishing its outer surface at the rate of ₹ 4 per 100 cm2, [take, 7t =3.14]

Given, inner radius of the hemispherical bowl = 24.7 cm

Thickness of metal sheet = 0.3 cm Now, outer radius of the hemispherical bowl r = 24.7 + 0.3 = 25 cm