A ball is thrown vertically upwards with a velocity of 49m/s calculate maximum height and time taken

The formula to be used to get maximum height is " v^{2} = u^{2} -2gh ", where v is final velocity

that is zero here when the ball reaches maximum height h. u is initial projection velocity.

hence we have, 0 = 49^{2} -2×9.8×h or h = 122.5 m

The formula to be used to get time to reach maximum height is " v = u - gt " ,

since v = 0 as mentioned above, we have t = u/g = 49/9.8 = 5 s