Let A = [ 2 5 3 4 ] B = [ 2 5 3 4 ] c = [ 2 5 3 4 ] . Find each of the following

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April 12, 2019

The number of all possible matrices of order 3 x 3 with each entry 0 or 1 is:

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April 12, 2019

Which of the given values of [ 3x + 7 5 y + 1 2  3x] = [ 0 y  2 8 4 ]

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April 12, 2019

Tan1 (x/y)  tan1 (x  y/x + y) is equal to:

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April 12, 2019

X then x is equal to:

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April 12, 2019

Sin (tan1 x), x < 1 is equal to:

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April 12, 2019

Solve the equation: tan1(1  x/1 + x) = 1/2 tan1 x, (x >0)

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April 12, 2019

Solve the equation: 2tan1(cos x) = tan1(2cosec x)

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April 12, 2019

Prove that: 9π/8  9/4 sin1 1/3 = 9/4 sin1 2√2/3

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April 12, 2019

Prove that: tan1 (√1 + x  √1  x/√1 + x + √1  x) = π/4  1/2cos1 x, 1/√2 ≤ x ≤ 1

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April 12, 2019

Prove that: cot1 (√1 + sin x + √1  sin x /√1 + sin x  √ 1  sin x ) = x/2, x ∈ (0, π/4)

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April 12, 2019

Prove that: tan1 √x = 1/2cos1(1  x /1 + x), x ∈ [0,1]

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April 12, 2019

Prove that: tan1 1/5 + tan1 1/7 + tan1 1/3 + tan1 1/8 = π/4

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April 12, 2019

Prove that: tan1 63/16 = sin1 5/13 + cos1 3/5

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April 12, 2019

Prove that: cos1 12/13 + sin1 3/5 = sin1 56/65

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April 12, 2019

Prove that: cos1 4/5 + cos1 12/12 = cos1 33/65

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April 12, 2019

Prove that: sin1 8/17 + sin1 3/5 = tan 1 77/36

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April 12, 2019

Prove that: 2sin1 3/5 = tan1 24/7

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April 12, 2019

Find the value of tan1(tan7π/6)

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April 12, 2019

Find the value of cos1(cos 13π/6)

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April 12, 2019

Sin[π/3  sin1 (1/2) ] is equal to:

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April 12, 2019

Cos1 (cos7π/6) is equal to:

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April 12, 2019

Find the values of tan(sin1 3/5 + cot1 3/2)

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April 12, 2019

Find the values of each of the expressions tan1(tan 3π/4)

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April 12, 2019

Find the values of the expressions sin1(sin 2π/3)

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April 12, 2019

If tan1 x  1/x  2 + tan1 x + 1 / x + 2 = π/4, then find the value of x

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April 12, 2019

If sin( sin1 1/5 + cos1 x) = 1 , then find the value of x

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April 12, 2019

Find the values of tan1/2[sin1 2x/1+x2 + cos1 1y2/1+y2], x < 1, y > 0 and xy < 1

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April 12, 2019

Find the values of cot(tan1 a = cot1 a)

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April 12, 2019

Find the values of each of the following: tan1[2cos(2sin1 1/2)]

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April 12, 2019
