Whenever a reaction between an oxidising agent and a reducing agent

cbse
redoxreactions

#1

Whenever a reaction between an oxidising agent and a reducing agent is carried out, a compound of lower oxidation state is formed if the reducing agent is in excess and a compound of higher oxidation state is formed if the oxidising agent is in excess. Justify this statement giving three illustrations.


#2

Therefore, when ${ P }{ 4 }$ (reducing agent) is in excess,
${ PCl }
{ 3 }$ is formed in which oxidation state of P is + 3 and if
${ Cl }{ 2 }$ (oxidising agent) is in excess,
${ PCl }
{ 5 }$ is formed in which oxidation state of P is + 5. Other two examples are
(ii) C is a reducing agent while ${{O}{2}}$ is an oxidising agent.

When reducing agent C is in excess, a compound CO of lower oxidation state is formed, if oxidising agent ${{O}
{2}}$ is in excess, a compound
${{CO}{2}}$ of higher oxidation state is formed.
(iii) Na is a reducing agent while ${{O}
{2}}$ is an oxidising agent.