The resistance of a conductivity cell containing 0.001 M

cbse
electrochemistry

#1

The resistance of a conductivity cell containing 0.001 M KCl solution at 298 K is 1500 Ω. What is the cell constant if the conductivity of 0.001 M KCl solution at 298 K is 0.146 x ${{10}^{-3}}$ S ${{cm}^{-1}}$?


#2

Given, conductivity, K= 0.146x${{10}^{-3}}$ S ${{cm}^{-1}}$ Resistance, R = 1500 Ω
.’. Cell constant = K X R
= 0.146 x${{10}^{-3}}$ X1500 = 0.219 ${{cm}^{-1}}$