The reactant which is entirely consumed in reaction is known as limiting reagent. In the reaction

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#1

The reactant which is entirely consumed in reaction is known as limiting reagent. In the reaction
2A + 4B —> 3C + 4D
when 5 moles of A react with 6 moles of B, then
(i) Which is the limiting reagent ?
(ii) Calculate the amount of C formed.


#2

2A + 4B —> 3C + 4D
Here, 2 moles of A reacts with 4 moles of B. Therefore,
5 moles of A reacts with 4/2x5 =10 moles of B.
But,
we have 6 moles of ‘B’
(i) It means ‘B’ is limiting reactant
(ii) 4 moles of ‘B’ gives 3 moles of C.
Hence, 6 moles of ‘B’ gives
3/4 X6 = 18/4=9/2== 4.5 moles of ‘C’