The diameter of zinc atom is 2.6 A. Calculate

(i) radius of zinc atom in pm and

(ii) number of atoms present in a length of 1.6 cm if the zinc atoms are arranged side by side lengthwise

# The diameter of zinc atom is 2.6 A

**prasanna**#1

**prasanna**#2

(i) Diameter of Zn atom = 2.6 A = 2.6 X ${{10}^{-10}}$ m

Radius of Zn atom = 2.6 x ${{10}^{-10}}$ m /2 = 130 pM

(ii)Given, length = 1.6 cm= 1.6x ${{10}^{-2}}$m

Number of Zn atoms in 1.6 x${{10}^{-2}}$ m

= 1.6 x ${{10}^{-2}}$ / 2.6 ${{10}^{-10}}$ = 6.154 x ${{10}^{-7}}$ atoms