tan^2x + tanx - 12 = 0?
Answer:
tan^2x + tanx -12 = 0
tan^2x+ 4tanx - 3tanx - 12 = 0
(tanx+4) (tanx-3) =0
tanx =-4 or tanx =3
x= - taninverse(4) or x = taninverse(3) [I have used that taninverse of -4 is - taninverse(4).]
Alternatively, if you are too lazy to factorize, you can use the formula for the roots of quadratic equation to get the two roots for tanx.
