Suppose that salaries for recent graduates of one university have a mean of $25,500 with a standard deviation of $1050. Using Chebyshev’s Theorem, what is the minimum percentage of recent graduates who have salaries between $22,350 and $28,650? Round your answer to one decimal place.
Subtract mean from highest value:
Divide 3150 by standard deviation (1050) to get k
Use Chebyshev’s Theorem to determine percent:
%=8/9 or 88.9%