passing through (-8,5) and the parallel to the line whose equation is 5x-3y-7=0. I need to know the equation of the line in general form.
I know the equation of the line in point slope form is y-5=5/3(x+8)
General form for the equation of a line is given as Ax + By + C=0 where A, B, and C are three real numbers.
As you have already found the equation in point slope form (which is correct as I have crosschecked it), we just need to transform it into general form.
y-5 = 5/3(x+8)
y = 5/3x + 40/3 + 5
3y = 5x + 40+15
3y = 5x+55
5x-3y+55 = 0 is the equation of line in general form.