In the laboratory, a volume of gas measures 600 mL at 22 C and 735 mm of pressure. What new volume will be established if the gas is placed under standard conditions (STP)?
so at first we have to convert celcius to kelvin , mL to L and mm Hg to kPa.
22 C = 295 K, 600mL= 0.6 L, 735 mm Hg = 97.9 kPa so then we need to use the combined gas law which is the following: (V1 P1)/T1= (V2 P2)/T2 so then we know that the pressure and the temperature at STP are 273 K and 101.3 kPa. so then we will plug in the numbers and we will get this (0.6 x 97.9 kPa)/295K = (V2 x 101.3 kPa)/273K and so V2 = 0.54 mL