Make a conjecture about each patter, write the next two items?
1/6, 1/3, 1/2, 2/3 …
To find the next two items in the sequence we need to find out how each term is chanced. The first term is 1/6, the second term is 2/6, the next term is 3/6. Based on this we can see a pattern. Any number in this sequence will be the number of the term you are on divided by six. So it would go like this: 1/6, 2/6, 3/6, 4/6, 5/6, 6/6, 7/6 and so on forever.
You can even write a formula for this sequence which would be written as t(n) = n/6. The way this works is lets say you want to find the 1st term in the sequence you just plugin 1 for the term n. There for t(1) = 1/6, where t(1) equals the first term. If you want to do this for the 5th and 6th term of the sequence it would go like this: t(5) = 5/6 t(6) = 6/6.
1/6, 2/6, 3/6, 4/6,… 5/6, 6/6 (1)