Look at the graphs (a) to (d) carefully and state with reasons, which of these cannot possibly represent one-dimensional motion of a particle?

# Look at the graphs (a) to (d) carefully and state

**prasanna**#1

**prasanna**#2

(a) No, graph (a) is not representing one-dimensional motion of a particle, because graph shows two different positions of the particle at same instant of time. (At time ${ t }*{ 1 }$, particle is at positions P and Q and at time
${ t }*{ 2 }$, particle is at positions R and S), which is not possible.

(b) No, graph (b) cannot represent one-dimensional motion of a particle, because graph shows one positive velocity (${ v }*{ 1 }$) and another negative velocity
(-${ v }*{ 2 }$) of the particle at the same instant of time {

${ t }

*{ 1 }$) which is not possible.*

© No, graph © cannot represent one-dimensional motion of a particle, because graph shows negative speed of the particle but speed cannot be negative.

{d) No, graph (d) cannot represent one-dimensional motion of a particle, because graph shows that total path length increases from time t = 0 to t =${ t }{ 1 }$, but decreases from t =

© No, graph © cannot represent one-dimensional motion of a particle, because graph shows negative speed of the particle but speed cannot be negative.

{d) No, graph (d) cannot represent one-dimensional motion of a particle, because graph shows that total path length increases from time t = 0 to t =${ t }

${ t }

*{ 1 }$ to t =*

${ t }{ 2 }$. But total path length of a moving particle can never decrease with time.

${ t }