Let A and B be 3 × 3 matrices, with detA D = 3 and detB = 4. Use properties of determinants (in the text and in the exercises above) to compute. det 5A.
From the properties of the determinant, we know that det(kA)=k^ndetA, where n is the order of matrix. Therefore det(5A)=5^3detA=125*3=375