In one scenario, it is calculated the astronauts may generate as much as 100.0 moles of carbon dioxide. In addition, it is determined that the scrubbers are only 80% efficient. Under these circumstances, how many grams of lithium hydroxide are required to ensure complete remove the carbon dioxide?
CO2 (g) + 2LiOH (s) -> Li2CO3 (s) + H2O (l)
100 mol CO2*2mol LiOH= 200 mol LiOH
200 mol/0.8= 250 mol LiOH required to completely remove CO2
250 mol LiOH*24g/mol= 6,000 g LiOH