In a simple model of the hydrogen atom, the electron revolves in a circular orbit around the proton with a speed of 2.5 ✕ 106 m/s. Determine the radius of the electron’s orbit.
Answer:
F = mv^2/r
F = kq1q2/r^2
F is the force of attraction between the electron and proton
m is the mass of the electron
v is the velocity it spins
r is the radius
(1.6x10^-19)(1.6x10^-19)(8.99x10^9)/((9.11x10^-31)*(2.5x10^6)^2)
= 0.404x10^-10 m
