In 96.0 gm of sulphur calculate

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#1

In 96.0 gm of sulphur calculate (i) the number of gram atoms of the element (ii) the number of gram , molecules, if a molecule of sulphur has the formula,Sg, (iii) the number of atoms of sulphur, and (iv) the „ number of molecules.
(At wt S = 32, Avogadro’s number, N = 6-02 X ${{10}^{23}}$ molecules per mole),


#2

(i) Atomic weight of sulphur = 32 1 gm atom of sulphur = 32 gm
No. of gram atoms in 96 gm of sulphur = 96 /32= 3.
(ii) Molecular weight of ${{S}_{8}}$ = 32 x 8 = 256
.’. No. of gram atoms in 96 gm of sulphur = 96/256 = 0.375.
(iii) 32 gm (1 gm atom) of sulphur contain 6.02 x ${{10}^{23}}$ atoms.
96 gm of sulphur contains 6.02/32 x 96 x ${{10}^{23}}$ = 1.806 x ${{10}^{24}}$ atoms
(iv) 256 gm (1 gm molecule) of sulphur contain 6.02 x ${{10}^{23}}$ molecules
96 gm of sulphur contains 6.02/256 x 96 x ${{10}^{23}}$ =2.257 x ${{10}^{23}}$ molecules.