If ten volume of dihydrogen gas reacts with five volume of dioxygen gas, how many volumes of water vapour would be produced?



According to Gay Lussac’s law of gaseous volumes, 2 volume of dihydrogen react with 1 volume of ${{O}_{2}}$ to produce 2 volume of water vapour. Therefore, 10 volume of dihydrogen on reaction with 5 volume of dioxygen will produce 10 volume of water vapour.