If 3.34 m^3 of a gas initially at STP is placed under a pressure of 3.15 atm, the temperature of the gas rises to 34.8 degrees Celsius?
Are you asking what the new volume of the gas is?
PV=nRT allows us to find the original number of moles. We also need to know that 1 cubic meter is 1000 liters, and that STP is at 1 atm pressure, 273.15 degrees Kelvin
(1 atm)(3340 L) = n(0.082057)(273.15)
We can now easily solve for n (number of moles), which is 3340/8.314/273.15 = 149 moles
Now we can solve for the new volume:
(3.15 atm)(V) = (149 moles)(0.082057)(273.15 + 34.8) = 1195.3 L or 1.195 m^3 of gas