If 22.85g of sodium hydroxide reacts completely with 20.82g of hydrochloric acid to form 10.29g of water, what mass of sodium chloride is formed during the reaction?
mass of the reactants = mass of the products <- law of the conservation of mass. So 22.85 (mass NaOH) + 20.82 (mass HCl) = 10.29 (mass H20) + mass NaCl. Solve for mass NaCl 22.85+20.82-10.29 = mass NaCl. final answer–>mass NaCl = 33.38 <-final answer