**How do you find dy/dx of xy+siny=x^2 ?**

**Answer:**

(2x-y) / (x+cosy) this is the answer look at the Implicit Differentiation …

we used product role (xy)

diffrentiate w.r.t “x”

(x d/dx y +y dx/dx) + d/dx ( siny) = d/dy( x^2)

X DY/DX +1 +cosy dy/dx = 2x

x dy/dx +cosy dy/dx=2x-1

dy/dx ( x+cosy) =2x-1

dy/dx=2x-1/x+cosy ans