how do i solve 2 over x minus 3 minus 4 over x plus 3= 8 over x squared minus 9?
Your denominators are (x-3), (x+3), and (x^2-9), correct? If so, you must multiply all pieces of the equation by the Least Common Denominator, which is (x-3)(x+3). This is also what x^2-9 factors to.
As a result the equation becomes: 2(x+3) - [4(x-3)] = 8
Solve this by distributing… : 2x+6-4x+12=8
Combine like terms: -2x+18=8
Subtract 18 from both sides: -2x=-10
Finally divide by -2: x=5