How come the limit of (2-3(0.8)^n ) as n approaches infinity equals 2 ??
0.8^n equals zero as n goes to infinity. If any number greater than one is raised to infinity then it goes to infinity, 1^infinity equals 1, and any number less than 1^infinity equals zero.
therefore it’s basically lim n to infinity (2-3(0)) which is just 2 since 3 times zero equals zero.