**Given sin θ = k, 3π/2<θ<2π. If sin β = k, which could be the value of β?**

**A. 2π – θ**

**B. 3π – θ**

**C. π + θ**

**D. θ - π**

**Answer:**

Answer is b. 3π – θ

Because sin 3π can be written as 2π + π

And sin 2 π + any angle is equal to sin of that angle

Thus it becomes sin π - theta.

And as it is given that sin and sin beta are equal to k. And sin π - theta is always equal to sin theta…