Given sin θ = k, 3π/2<θ<2π. If sin β = k, which could be the value of β?

sin-k-322-if-sin-k

#1

Given sin θ = k, 3π/2<θ<2π. If sin β = k, which could be the value of β?
A. 2π – θ
B. 3π – θ
C. π + θ
D. θ - π

Answer:

Answer is b. 3π – θ
Because sin 3π can be written as 2π + π
And sin 2 π + any angle is equal to sin of that angle
Thus it becomes sin π - theta.
And as it is given that sin and sin beta are equal to k. And sin π - theta is always equal to sin theta…