**g(x)=(2x+4)^3(x-6)**

**-Find the crititcal number of g**

**-For what values of x is g increasing?**

**Identify the x-coordinate of the critical points at which g has relative minimum**

**Answer:**

-Critical values are where the derivatives are equal to 0. x=-2 & x=4

-g is increasing when the derivate is positive and decreasing when the derivative is negative. It is increasing when x>4

-relative minimum is always at a critical point. It is where the derivative switches signs from negative to positive. In this case, it is at x = 4