G(x)=(2x+4)^3(x-6) Find the crititcal number of g For what values of x is g increasing?

x-coordinate
crititcal-number

#1

g(x)=(2x+4)^3(x-6)
-Find the crititcal number of g
-For what values of x is g increasing?
Identify the x-coordinate of the critical points at which g has relative minimum

Answer:

-Critical values are where the derivatives are equal to 0. x=-2 & x=4
-g is increasing when the derivate is positive and decreasing when the derivative is negative. It is increasing when x>4
-relative minimum is always at a critical point. It is where the derivative switches signs from negative to positive. In this case, it is at x = 4