Four times the number of yellows equaled 76 reduced by 6 times the number of reds. If there were 4 more yellows than reds


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Four times the number of yellows equaled 76 reduced by 6 times the number of reds. If there were 4 more yellows than reds, How many of each were there?

Answer:

Two equations, two unknowns. From the first sentence y=r+4
and from the second sentence 4y=76−6r.
Solving we get:
4(r+4)=76−6r−>4r+16=76−6r−>10r=60=−>r=6

Then since r = 6,
y=r+4y=6+4y=10