**Four times the number of yellows equaled 76 reduced by 6 times the number of reds. If there were 4 more yellows than reds, How many of each were there?**

**Answer:**

Two equations, two unknowns. From the first sentence y=r+4

and from the second sentence 4y=76−6r.

Solving we get:

4(r+4)=76−6r−>4r+16=76−6r−>10r=60=−>r=6

Then since r = 6,

y=r+4y=6+4y=10