Find the value of k if (3x+k)^3+(4x-7)^2 has a remainder of 33 when divided by x-3

3xk34x-72

#1

Find the value of k if (3x+k)^3+(4x-7)^2 has a remainder of 33 when divided by x-3

Answer:

Put x=3 in the given expression we get (9+k)^{3} + 5^{2} =33
or (9+k)^{3} + 25=33
(9+k)^{3}=8
9+k=2
k=-7