Find the limit. lim as n approaches infinity. n sigma i=1. (2/n)[((2i/n)^3)+5((2i)/n)]

2-n-2i-n-3-5-2i-n33

#1

find the limit. lim as n approaches infinity. n sigma i=1. (2/n)[((2i/n)^3)+5((2i)/n)]

Answer:

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