Two charges of+25 x ${{10}^{-9}}$ C and - 25 x ${{10}^{-9}}$ C are placed 6 m apart. Find the electric field at a point 4 m from the centre of the electric dipole (i) on axial line (ii) on equatorial line.

# Find the electric field at a point 4 m

**prasanna**#2

Here, q = 25 x ${{10}^{-9}}$ C

2a = 6m , r = 4m

p = q(2a) = 25 x ${{10}^{-9}}$ x 6 = 1.5 x ${{10}^{-7}}$ C