**Find the derivative. F(t)=te^(5+2t^5)**

**Answer:**

F’(t)= ((t)((10t^4)e^(5+(2t^5)))+ (1)(e^(5+(2t^5)))

F’(t)= 10(t^5)(e^(5+2t^5)) + e^(5+2t^5)

F’(t)= e^(5+2t^5)(10(t^5)+1)

**Find the derivative. F(t)=te^(5+2t^5)**

**Answer:**

F’(t)= ((t)((10t^4)e^(5+(2t^5)))+ (1)(e^(5+(2t^5)))

F’(t)= 10(t^5)(e^(5+2t^5)) + e^(5+2t^5)

F’(t)= e^(5+2t^5)(10(t^5)+1)