Find the derivative. F(t)=te^(5+2t^5)

derivative
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#1

Find the derivative. F(t)=te^(5+2t^5)

Answer:

F’(t)= ((t)((10t^4)e^(5+(2t^5)))+ (1)(e^(5+(2t^5)))
F’(t)= 10(t^5)(e^(5+2t^5)) + e^(5+2t^5)
F’(t)= e^(5+2t^5)(10(t^5)+1)