Find the area of the surface. The part of the surface z = 8 + 5x + 2y^2 that lies above the triangle with vertices (0, 0), (0, 1), (2, 1)

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#1

Find the area of the surface. The part of the surface z = 8 + 5x + 2y^2 that lies above the triangle with vertices (0, 0), (0, 1), (2, 1).

Answer:

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