**Find the area of an isosceles trapezoid if the bases have lengths 12 and 17 and the base angles measure 60 degrees?**

**Answer:**

So, if you position the trapezoid with the long base on the bottom, you have to draw an altitude from one of the top vertices down. This creates a 30-60-90 triangle. The side of that triangle that is part of the long base equals half the difference between the bases, or (17-12)/2 = 2.5.

2.5 is the short leg of the triangle, and the altitude drawn is the long leg. The altitude is

h = 2.5√3

So, the area of a trapezoid is (1/2)(b1+b2)h

=(1/2)(12+17)(2.5√3)

=36.25*√3