Find 3 consecutive integers such that 5 times the sum of the first and the third is 14 greater than 8 times the second

consecutive-integers

#1

Find 3 consecutive integers such that 5 times the sum of the first and the third is 14 greater than 8 times the second

Answer:

3 consecutive integers x, x + 1, and x + 2

5(x + x + 2) = 8(x + 1) + 14
10x + 10 = 8x + 8 + 14
10x + 10 = 8x + 22
10x = 8x + 12
2x = 12
x = 6

Integer 1 = 6
Integer 2 = 7
Integer 3 = 8