**Find 3 consecutive integers such that 5 times the sum of the first and the third is 14 greater than 8 times the second**

**Answer:**

3 consecutive integers x, x + 1, and x + 2

5(x + x + 2) = 8(x + 1) + 14

10x + 10 = 8x + 8 + 14

10x + 10 = 8x + 22

10x = 8x + 12

2x = 12

x = 6

Integer 1 = 6

Integer 2 = 7

Integer 3 = 8